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Question

For the reaction 2H₂S(g) + 3O₂(g) → 2H₂O(l) + 2SO₂(g) , Δ ng = -3 . If Δ H = -1124.00 kJ/mol at 298 K, what is Δ U ? ( R = 8.314 J/mol·K )

Options

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Explanation

RT = 8.314 × 298 × 10⁻³ = 2.4776 kJ/mol . Using Δ H = Δ U + Δ ng RT , Δ U = -1124.00 - (-3 × 2.4776) = -1124.00 + 7.4328 = -1116.57 kJ/mol .