Practice question
Question
For A(g) + 2B(g) <=> 2C(g) , Kp = 1 at 400 K. If PA = 0.5 atm , PB = 1 atm initially, what is PC at equilibrium?
Explanation
Let PC = 2x , PA = 0.5 - x , PB = 1 - 2x . Kp = ((PC)²/PA PB²) = ((2x)²/(0.5 - x)(1 - 2x)²) = 1 , 4x² = (0.5 - x)(1 - 2x)² , x ≈ 0.25 , PC = 0.5 atm .
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