Practice question
Question
For a reaction with K = 0.01 at 298 K, calculate Δ G°. (R = 8.314 J/mol·K)
Explanation
Δ G° = -RT ln K = -8.314 × 298 × ln(0.01) = -8.314 × 298 × (-4.605) = 11403 J/mol = 11.4 kJ/mol.
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