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Question

For 2A(g) <=> B(g) , Kc = 0.04 at 300 K. If 0.5 mol A is in a 1 L vessel, what is [B] at equilibrium?

Options

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Explanation

Initial: [A] = 0.5 M , [B] = 0 . Let x = [B] , [A] = 0.5 - 2x . Kc = ([B]/[A]²) = (x/(0.5 - 2x)²) = 0.04 , x = 0.04 (0.5 - 2x)² , sqrtx = 0.2 (0.5 - 2x) , x ≈ 0.04 M .