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Practice question

MCQ

Question

For 2A(g) + B(g) <=> 2C(g) , Kp = 16 at 500 K. If initial pressures are PA = 2 atm , PB = 1 atm , what is PC at equilibrium?

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Explanation

Let PC = 2x , PA = 2 - 2x , PB = 1 - x , total pressure = 3 - x . Kp = ((PC)²/PA² PB) = ((2x)²/(2 - 2x)² (1 - x)) = 16 , (4x²/4(1 - x)² (1 - x)) = 16 , (x²/(1 - x)³) = 4 , (x/1 - x) = 2 , x = 2 - 2x , 3x = 2 , x = (2/3) , PC = 2 × (2/3) = 1.33 atm .

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