Practice question
Question
A weak acid HB ( Ka = 1.0 × 10⁻⁶ ) is mixed with 0.03 M NaOH in a 3:1 volume ratio (acid:base). If the final [HB] = 0.08 M , what is the pH?
Explanation
Total volume = 4V, initial [HB] = 0.107 M , [B-] = (0.03V/4V) = 0.0075 M , pKa = 6 , pH = 6 + log (0.0075/0.08) = 6 - 1.03 = 4.97 .
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