Practice question
Question
A system at constant volume absorbs 208 J of heat, and its temperature increases from 300 K to 310 K. What is Cv ? (1 mol diatomic gas)
Explanation
For a diatomic ideal gas at constant volume, Δ U = qv = nCvΔ T . Given qv = 208 J , n = 1 mol , Δ T = 310 - 300 = 10 K , we get 208 = 1 × Cv × 10 , so Cv = 208 / 10 = 20.8 J/mol·K , typical for a diatomic gas ( Cv ≈ 2.5R ).
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