Practice question
Question
A solution is prepared by dissolving 18 g of a solute in water to make 500 mL of solution with a density of 1.2 g/mL. If the molality is 0.2 mol/kg, what is the molar mass of the solute?
Explanation
Total mass = 500 × 1.2 = 600 g . Mass of water = 600 - 18 = 582 g = 0.582 kg . Molality = (moles/0.582) = 0.2 . Moles = 0.2 × 0.582 = 0.1164 . Molar mass = (18/0.1164) ≈ 154.64 g/mol .
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