Practice question
Question
A reaction’s rate increases by 2 times when the temperature rises from 310 K to 320 K. What is the activation energy (R = 8.314 J mol⁻¹ K⁻¹)?
Explanation
log 2 = Ea/(2.303R) × (10)/(310×320) → Ea ≈ 57.2 kJ mol⁻¹.
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