Practice question
Question
A first-order reaction has a rate constant of 0.0115 min⁻¹. What is the time for 70% completion?
Explanation
70% completion means 30% remains, [R]/[R]₀ = 0.3, [R]₀/[R] ≈ 3.333. t = (2.303/0.0115) log 3.333 ≈ 105 min.
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