Practice question
Question
A current of 0.5 A deposits 0.3175 g of Cu from CuSO₄ in 3860 s. What mass of Mg would be deposited from MgCl₂ with the same charge? (Atomic masses: Cu = 63.5 g/mol, Mg = 24 g/mol, F = 96500 C/mol)
Explanation
Charge = 0.5 × 3860 = 1930 C . Cu: Cu²⁺ + 2e⁻ → Cu , Moles = (0.3175/63.5) = 0.005 mol , Charge = 0.005 × 2 × 96500 = 1930 C , matches. Mg: Mg²⁺ + 2e⁻ → Mg , Moles = (1930/96500 × 2) = 0.01 mol , Mass = 0.01 × 24 = 0.24 g .
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