Practice question
Question
A 0.1 M solution of K₃PO₄ (assuming complete dissociation) has an osmotic pressure of 0.984 atm at a certain temperature. What is the temperature? ( R = 0.0821 L atm mol⁻¹ K⁻¹ )
Explanation
For K₃PO₄, i = 4 (3K⁺ + PO₄³⁻). Pi = i · M · RT . 0.984 = 4 × 0.1 × 0.0821 × T . T = (0.984/0.4 × 0.0821) ≈ 30 K .
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