A 3kg particle moves with velocity v\=6i^m/s at r\=2j^m. What is the magnitude of its angular momentum about the origin?
L = r×p = |i^j^k^020600| = k^(0×0−2×6) = −12k^kg m2/s. Magnitude = 12kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 12 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.