In the cross AaBBcc x aaBbCc, what is the probability of an offspring that is aaBbcc?
Independent assortment predicts probability product of individual loci. Cross Aa x aa gives 1/2 aa, BB x Bb gives 1/2 Bb, cc x Cc gives 1/2 cc. Multiplying 1/2 × 1/2 × 1/2 equals 1/8 chance of aaBbcc offspring genotype.
Ref: Pierce, Genetics: A Conceptual Approach, 7th Edition, Chapter 3, Mendelian Genetics and Probability, and Griffiths et al., Introduction to Genetic Analysis, explains independent assortment product rule for cross AaBBcc x aaBbCc calculating probability of aaBbcc as 1/8 using monohybrid probabilities,