Practice question
Question
In the cross AaBBcc x aaBbCc, what is the probability of an offspring that is aaBbcc?
Explanation
Independent assortment predicts probability product of individual loci. Cross Aa x aa gives 1/2 aa, BB x Bb gives 1/2 Bb, cc x Cc gives 1/2 cc. Multiplying 1/2 × 1/2 × 1/2 equals 1/8 chance of aaBbcc offspring genotype.
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