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NEET MOCK TEST 1

NEET Mock Test 1 is a practice test that brings Physics, Chemistry and Biology questions together in a single attempt. It gives you a way to sit the paper end to end, get used to answering across subjects, and see which areas need more revision once you check your results.

180 questions

CHEMISTRY

A solution contains 5 g of glucose dissolved in 95 g of water. What is the mass percentage of glucose?

Given: A solution contains 5 g of glucose dissolved in 95 g of water. What is the mass percentage of glucose? These values define the system as per NCERT data. Formula: Total mass = 5 + 95 = 100 g. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Mass % = (5 / 100) × 100 = 5%. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Solutions, Topic: Concentration terms and colligative properties.

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PHYSICS

A mixture contains 1 mole of helium and 1 mole of oxygen at 300 K. What is the ratio of their partial pressures?

Given: A mixture contains 1 mole of helium and 1 mole of oxygen at 300 K. What is the ratio of their partial pressures? These values define the system as per NCERT data. Formula: For ideal gases, P = μ RT/V, partial pressure propto μ (since V and T are same). This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Ratio fracP_{HeP_{O_2 = fracμ_{Heμ_{O_2 = 1/1 = 1. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Units and Measurements and Physical World, Topic: Dimensional analysis and fundamental principles.

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CHEMISTRY

The K_a of HF is 6.8 × 10⁻⁴. What is the pH of a 0.1 M HF solution?

Given: The K_a of HF is 6.8 × 10⁻⁴. What is the pH of a 0.1 M HF solution? These values define the system as per NCERT data. Formula: K_a = frac[H+][F-][HF] approx x²/0.1, 6.8 × 10⁻⁴= x²/0.1, x² = 6.8 × 10⁻⁵, x approx 8.25 × 10⁻³. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: pH = -log(8.25 × 10⁻³) approx 2.08 . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Solutions, Topic: Concentration terms and colligative properties.

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CHEMISTRY

A first-order reaction has a rate constant of 0.0462 min^{-1 . What is the half-life in minutes?

Given: A first-order reaction has a rate constant of 0.0462 min^{-1 . What is the half-life in minutes? These values define the system as per NCERT data. Formula: t_{1/2 = 0.693/k = 0.693/0.0462 = 15 min .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

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PHYSICS

The dimensional formula of work is [M L² T^{-2] . What is the dimensional formula of power?

Given: The dimensional formula of work is [M L² T^{-2] . What is the dimensional formula of power? These values define the system as per NCERT data. Formula: Power = Work/Time. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: [P] = [M L² T^{-2] / [T] = [M L² T^{-3] . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Laws of Motion, Work Energy Power, Gravitation and System of Particles, Topic: Newton's laws, work-energy theorem and rotational dynamics.

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PHYSICS

A rod of length 0.2 m moves at 5 m/s in a 0.3 T field perpendicular to its length. What is the induced emf?

Given: A rod of length 0.2 m moves at 5 m/s in a 0.3 T field perpendicular to its length. What is the induced emf? These values define the system as per NCERT data. Formula: Motional emf: varepsilon = B l v. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: varepsilon = 0.3 × 0.2 × 5 = 0.3 V . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Electromagnetic Induction, Alternating Current and Electromagnetic Waves, Topic: Induced emf, inductance and EM wave properties.

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CHEMISTRY

Calculate the boiling point elevation of a solution containing 6 g of urea ( NHâ‚‚CONHâ‚‚ ) in 100 g of water. ( K_b = 0

Given: Calculate the boiling point elevation of a solution containing 6 g of urea ( NH₂CONH₂ ) in 100 g of water. ( K_b = 0.52 K kg/mol, Molar mass of urea = 60 g/mol ) These values define the system as per NCERT data. Formula: Moles of urea = 6/60 = 0.1 mol. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Molality = 0.1/0.1 = 1 mol/kg . Δ T_b = 0.52 × 1 = 0.52 K . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.

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PHYSICS

A dipole with m = 0.5 A m² in B = 0.7 T at 60° has torque:

Given: A dipole with m = 0.5 A m² in B = 0.7 T at 60° has torque: These values define the system as per NCERT data. Formula: tau = m B sinθ. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Given: m = 0.5 A m², B = 0.7 T, θ = 60°, sin 60° = fracsqrt32 approx 0.866 . tau = 0.5 × 0.7 × 0.866 approx 0.3031 N m approx 0.30 N m . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Moving Charges and Magnetism and Magnetism and Matter, Topic: Magnetic field due to current loop, solenoid and magnetic dipole moment. Page number should be added only after verification from the.

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PHYSICS

The magnetic potential energy of a dipole with m = 0.4 A m² in a field B = 0.7 T at 180° is:

Given: The magnetic potential energy of a dipole with m = 0.4 A m² in a field B = 0.7 T at 180° is: These values define the system as per NCERT data. Formula: U_m = -m B cosθ. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Given: m = 0.4 A m², B = 0.7 T, θ = 180°, cos 180° = -1 . Substitute: U_m = -0.4 × 0.7 × (-1) = 0.28 J . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Moving Charges and Magnetism and Magnetism and Matter, Topic: Magnetic field due to current loop, solenoid and magnetic dipole moment. Page number should be added only after verification from the.

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