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NEET MOCK TEST 2

This is the second mock test set in the NEET practice series on Examtube. Attempt the questions the way you would in the actual exam, then go through your answers to check accuracy, pacing and the topics that still need revision.

180 questions

What is the degree of dissociation of 0.025 M methanoic acid if its molar conductivity is 46.1 S cm² mol⁻¹, given la

Given: What is the degree of dissociation of 0.025 M methanoic acid if its molar conductivity is 46.1 S cm² mol⁻¹, given lambda⁰(H^+) = 349.6 S cm² mol^{-1 and lambda⁰(HCOO^-) = 54.6 S cm² mol^{-1 ? These values define the system as per NCERT data. Formula: Lambda_m⁰ = 349.6 + 54.6 = 404.2 S cm² mol^{-1. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: α = Lambda_m/Lambda_m⁰ = 46.1/404.2 approx 0.114 . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

In combustion analysis, 0.36 g of a compound gave 0.36 g of Hâ‚‚O . What is the percentage of hydrogen? (Atomic masses:

Given: In combustion analysis, 0.36 g of a compound gave 0.36 g of H₂O . What is the percentage of hydrogen? (Atomic masses: H = 1, O = 16) These values define the system as per NCERT data. Formula: Molar mass of H₂O = 18 g/mol. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Mass of H = 2 × 0.36/18 = 0.04 g. Percentage = 0.04 × 100/0.36 = 11.11% . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

In the Dumas method, 0.5 g of a compound gave 112 mL of Nâ‚‚ at STP. What is the percentage of nitrogen? (Atomic mass: N

Given: In the Dumas method, 0.5 g of a compound gave 112 mL of N₂ at STP. What is the percentage of nitrogen? (Atomic mass: N = 14) These values define the system as per NCERT data. Formula: Mass of N₂ = 28 × 112/22400 = 0.14 g. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Mass of N = 0.14 g. Percentage = 0.14 × 100/0.5 = 28% . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

What is the mass percentage of sulfur in Na₂S₂O₃? (Atomic masses: Na = 23, S = 32, O = 16)

Given: What is the mass percentage of sulfur in Na₂S₂O₃? (Atomic masses: Na = 23, S = 32, O = 16) These values define the system as per NCERT data. Formula: Molar mass = (2 × 23) + (2 × 32) + (3 × 16) = 46 + 64 + 48 = 158 g/mol. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Mass of S = 2 × 32 = 64 g. % S = (64 / 158) × 100 ≈ 40.51%. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

What is the oxidation number of Cl in ClO₃^- ?

O is -2, total charge is -1. Let Cl be x : x + 3(-2) = -1, x - 6 = -1, x = +5 . This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

What is the pH of a 0.001 M Ba(OH)2 solution, assuming complete dissociation?

Given: What is the pH of a 0.001 M Ba(OH)2 solution, assuming complete dissociation? These values define the system as per NCERT data. Formula: [OH-] = 2 × 0.001 = 0.002 M, pOH = -log(0.002) approx 2.7. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: pH = 14 - 2.7 = 11.3 . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Solutions, Topic: Concentration terms and colligative properties.

What is the product when (CH₃)2NH reacts with HNO₂ ?

Given: What is the product when (CH₃)2NH reacts with HNO₂ ? These values define the system as per NCERT data. Formula: Secondary amines like (CH₃)2NH react with HNO₂ to form yellow oily N-nitrosoamines, (CH₃)2N-N=O, without gas evolution.. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

Which of the following amines reacts with CH₃COCl to form an amide?

Primary amines like CH₃CH₂NH₂ react with acetyl chloride ( CH₃COCl ) to form amides ( CH₃CONHCH₂CH₃ ), while tertiary amines do not. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Relevant Chemistry topic covering principles and examples as per NCERT.

Which complex shows ionization isomerism with [Co(NH₃)5SO₄]Br ?

Ionization isomerism involves different ions outside the coordination sphere. [Co(NH₃)5Br]SO₄ is an ionization isomer of [Co(NH₃)5SO₄]Br, as Br^- and SO₄^{2- switch positions.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Organic Chemistry - Basic Principles, Hydrocarbons and Reaction Mechanisms, Topic: Nomenclature, isomerism and reaction types.

A solenoid of 1000 turns/m and area 0.02 m² has μ_r = 2 . What is its self-inductance? ( μ_0 = 4π × 10⁻⁷ H/m )

Given: A solenoid of 1000 turns/m and area 0.02 m² has μ_r = 2 . What is its self-inductance? ( μ_0 = 4π × 10⁻⁷ H/m ) These values define the system as per NCERT data. Formula: L = μ_r μ_0 n² A l, assume l = 1 m. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: L = 2 × 4π × 10⁻⁷ × (1000)² × 0.02 × 1 = 0.05024 H approx 0.05 H . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Moving Charges and Magnetism and Magnetism and Matter, Topic: Magnetic field due to current loop, solenoid and magnetic dipole moment. Page number should be added only after verification from the.

A proton moves at 1.5 × 10⁷ m/s perpendicular to a field of 0.2 T . What is the radius of its path? (Mass = 1.67 × 1

Given: A proton moves at 1.5 × 10⁷ m/s perpendicular to a field of 0.2 T . What is the radius of its path? (Mass = 1.67 × 10⁻²⁷ kg, charge = 1.6 × 10⁻¹⁹ C ) These values define the system as per NCERT data. Formula: r = mv/qB. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: r = frac1.67 × 10⁻²⁷ × 1.5 × 10⁷¹.6 × 10⁻¹⁹ × 0.2 = frac2.505 × 10⁻²⁰³.2 × 10⁻²⁰= 0.7828 approx 0.78 m . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Units and Measurements and Physical World, Topic: Dimensional analysis and fundamental principles.

What is the molality of a solution containing 8 g of NaOH in 400 g of water? (Molar mass of NaOH = 40 g/mol)

Given: What is the molality of a solution containing 8 g of NaOH in 400 g of water? (Molar mass of NaOH = 40 g/mol) These values define the system as per NCERT data. Formula: Moles = 8 / 40 = 0.2 mol. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Mass of solvent = 0.4 kg. Molality = 0.2 / 0.4 = 0.5 m. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom and Periodicity, Topic: Mole concept, atomic models and periodic trends.