PHYSICS

PHYSICS

In a circuit, a 20 V battery with negligible internal resistance is connected across a cubical network of 12 resistors,

Given: In a circuit, a 20 V battery with negligible internal resistance is connected across a cubical network of 12 resistors, each 2 Ω . What is the total current? These values define the system as per NCERT data. Formula: Equivalent resistance of cube network: R_{eq = 5/6 R = 5/6 × 2 = 10/6 = 5/3 Ω. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Total current: I = fracVR_{eq = frac205/3 = 20 × 3/5 = 12 A . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Current Electricity, Topic: Resistivity, temperature dependence and circuit analysis.

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PHYSICS

A 3 kg mass moving at 12 m/s collides elastically with an identical stationary mass. What is the speed of the first mass

Given: A 3 kg mass moving at 12 m/s collides elastically with an identical stationary mass. What is the speed of the first mass after collision? These values define the system as per NCERT data. Formula: For equal masses in elastic collision, v_{1f = 0 m/s (first mass stops).. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Units and Measurements and Physical World, Topic: Dimensional analysis and fundamental principles.

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PHYSICS

A shell of mass 0.01 kg is fired from a gun of mass 50 kg with a muzzle speed of 100 m/s . What is the recoil speed of t

Given: A shell of mass 0.01 kg is fired from a gun of mass 50 kg with a muzzle speed of 100 m/s . What is the recoil speed of the gun? These values define the system as per NCERT data. Formula: Before firing: p_{initial = 0. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: By conservation of momentum, total momentum before and after firing is zero. . After firing: m_{shell v_{shell + m_{gun v_{gun = 0 . Substitute: 0.01 × 100 + 50 × v_{gun = 0 . 1 + 50 v_{gun = 0 Rightarrow v_{gun = -1/50 = -0.02 m/s . Recoil speed (magnitude) = 0.02 m/s . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Moving Charges and Magnetism and Magnetism and Matter, Topic: Magnetic field due to current loop, solenoid and magnetic dipole moment. Page number should be added only after verification from the.

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PHYSICS

A rectangular loop of sides 12 cm and 4 cm moves out of a 0.35 T field at 2 m/s perpendicular to the longer side. What i

Given: A rectangular loop of sides 12 cm and 4 cm moves out of a 0.35 T field at 2 m/s perpendicular to the longer side. What is the motional emf? These values define the system as per NCERT data. Formula: varepsilon = B l v, l = 0.04 m. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: varepsilon = 0.35 × 0.04 × 2 = 0.028 V . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Electromagnetic Induction, Alternating Current and Electromagnetic Waves, Topic: Induced emf, inductance and EM wave properties.

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PHYSICS

A spring of k = 200 N/m has a 0.5 kg mass. If E = 1 J, what is the amplitude?

Given: A spring of k = 200 N/m has a 0.5 kg mass. If E = 1 J, what is the amplitude? These values define the system as per NCERT data. Formula: Total energy: E = 1/2 k A². This is the standard NCERT relation for this phenomenon. Substitution & Calculation: 1 = 1/2 × 200 × A² Rightarrow 1 = 100 A² Rightarrow A² = 0.01 Rightarrow A = 0.1 m . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Laws of Motion, Work Energy Power, Gravitation and System of Particles, Topic: Newton's laws, work-energy theorem and rotational dynamics.

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PHYSICS

The magnetic potential energy of a dipole with m = 0.6 A m² in a field B = 0.2 T at 0° is:

Given: The magnetic potential energy of a dipole with m = 0.6 A m² in a field B = 0.2 T at 0° is: These values define the system as per NCERT data. Formula: U_m = -m B cosθ. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Given: m = 0.6 A m², B = 0.2 T, θ = 0°, cos 0° = 1 . Substitute: U_m = -0.6 × 0.2 × 1 = -0.12 J . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Moving Charges and Magnetism and Magnetism and Matter, Topic: Magnetic field due to current loop, solenoid and magnetic dipole moment. Page number should be added only after verification from the.

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PHYSICS

A solenoid with mutual inductance 0.22 H has a current change of 7 A/s in the primary coil. What is the induced emf in t

Given: A solenoid with mutual inductance 0.22 H has a current change of 7 A/s in the primary coil. What is the induced emf in the secondary coil? These values define the system as per NCERT data. Formula: varepsilon = M dI/dt = 0.22 × 7 = 1.54 V .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Moving Charges and Magnetism and Magnetism and Matter, Topic: Magnetic field due to current loop, solenoid and magnetic dipole moment. Page number should be added only after verification from the.

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PHYSICS

A circular loop of radius 0.13 m with 20 turns carries a current of 3.5 A . What is the magnetic field at the nter? ( μ

Given: A circular loop of radius 0.13 m with 20 turns carries a current of 3.5 A . What is the magnetic field at the nter? ( μ_0 = 4 π × 10⁻⁷ T m/A ) These values define the system as per NCERT data. Formula: Magnetic field B = μ_0 N I/2 R. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: B = frac4 π × 10⁻⁷ × 20 × 3.52 × 0.13 = frac28 π × 10⁻⁶⁰.26 = 1.0769 π × 10⁻⁴ approx 3.38 × 10⁻⁴ T . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Moving Charges and Magnetism and Magnetism and Matter, Topic: Magnetic field due to current loop, solenoid and magnetic dipole moment. Page number should be added only after verification from the.

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PHYSICS

Two parallel wires 0.12 m apart carry 7 A and 3 A in the same direction. What is the force per unit length? ( μ_0 = 4 Ï

Given: Two parallel wires 0.12 m apart carry 7 A and 3 A in the same direction. What is the force per unit length? ( μ_0 = 4 π × 10⁻⁷ T m/A ) These values define the system as per NCERT data. Formula: f = μ_0 I_1 I_2/2 π d. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: f = frac4 π × 10⁻⁷ × 7 × 32 π × 0.12 = frac84 × 10⁻⁷⁰.24 = 3.5 × 10⁻⁶ N/m . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Laws of Motion, Work Energy Power, Gravitation and System of Particles, Topic: Newton's laws, work-energy theorem and rotational dynamics.

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PHYSICS

A projectile is launched at 20 m/s at 53° . What is its maximum height? (Take g = 10 m/s², sin 53° = 0.8 )

Given: A projectile is launched at 20 m/s at 53° . What is its maximum height? (Take g = 10 m/s², sin 53° = 0.8 ) These values define the system as per NCERT data. Formula: Maximum height h_m = (v_0 sin θ_0)²/2g. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Given: v_0 = 20 m/s, sin 53° = 0.8, g = 10 m/s² . h_m = (20 × 0.8)²/2 × 10 = 16²/20 = 256/20 = 12.8 m . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Units and Measurements and Physical World, Topic: Dimensional analysis and fundamental principles.

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PHYSICS

A particle rotates about a fixed axis at a radius of 0.6 m with a linear speed of 7.2 m/s . What is its angular velocity

Given: A particle rotates about a fixed axis at a radius of 0.6 m with a linear speed of 7.2 m/s . What is its angular velocity? These values define the system as per NCERT data. Formula: v = omega r. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: v = 7.2 m/s, r = 0.6 m . omega = v/r = 7.2/0.6 = 12 rad/s . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Units and Measurements and Physical World, Topic: Dimensional analysis and fundamental principles.

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PHYSICS

The resistivity of insulators is typically in the range:

Insulators have high resistivity ( 10¹⁰ to 10¹⁹Ω m ) or low conductivity ( 10⁻¹¹ to 10⁻¹⁹ S m^{-1 ), preventing significant current flow. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Current Electricity, Topic: Resistivity, temperature dependence and circuit analysis.

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