Practice question
Question
In a circuit, a 20 V battery with negligible internal resistance is connected across a cubical network of 12 resistors, each 2 Ω . What is the total current?
Explanation
Given:
In a circuit, a 20 V battery with negligible internal resistance is connected across a cubical network of 12 resistors, each 2 Ω . What is the total current?
These values define the system as per NCERT data.
Formula:
Equivalent resistance of cube network: R_{eq = 5/6 R = 5/6 × 2 = 10/6 = 5/3 Ω.
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
Total current: I = fracVR_{eq = frac205/3 = 20 × 3/5 = 12 A .
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
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