Latest questions in this category.
CH₃CH₂COOH (propanoic acid) contains the -COOH group, characteristic of carboxylic acids.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Electronic Effects - Inductive Mesomeric Hyperconjugation and Resonance
Heterolytic cleavage results in ions (e.g., Br⁺ and Br⁻) due to unequal sharing of electrons.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Electronic Effects - Inductive Mesomeric Hyperconjugation and Resonance
Prussian blue indicates nitrogen (NaCN), and yellow precipitate (AgI) indicates iodine.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Electronic Effects - Inductive Mesomeric Hyperconjugation and Resonance
In CH₃CHO, the carbon in CH₃ has four single bonds (three H, one C), indicating sp³ hybridization and a tetrahedral shape.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Electronic Effects - Inductive Mesomeric Hyperconjugation and Resonance
H⁺ adds to CH₃CH=CHCH₃ (but-2-ene), forming CH₃CH⁺CH₂CH₃ (secondary carbocation), stabilized by hyperconjugation.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Electronic Effects - Inductive Mesomeric Hyperconjugation and Resonance
Cleavage at CH₂Cl forms CH₃CH₂CH₂CH₂CH₂⁺ (primary). A hydride shift to CH₃CH₂CH₂CH⁺CH₃ (secondary) increases stability via hyperconjugation.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Electronic Effects - Inductive Mesomeric Hyperconjugation and Resonance
(CH₃)₂CH⁺ (secondary) is more stable than primary carbocations due to hyperconjugation with adjacent C-H bonds.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Electronic Effects - Inductive Mesomeric Hyperconjugation and Resonance
This is a nucleophilic substitution reaction where OH⁻ replaces Br⁻ on the carbon atom.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Electronic Effects - Inductive Mesomeric Hyperconjugation and Resonance
In CH₃CH₂C≡CCH₂CH₃ (pent-2-yne), sp³ carbons (CH₃, CH₂) have 109.5°, while sp carbons (C≡C) have 180°. The first (CH₃) has the smallest.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Electronic Effects - Inductive Mesomeric Hyperconjugation and Resonance
Cleavage at C-Cl forms CH₃CH₂CH₂CH⁺CH₃ (secondary). A hydride shift to CH₃CH₂CH⁺CH₂CH₃ (secondary) is equally stable, but +I effect from alkyl groups favors it slightly more.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Electronic Effects - Inductive Mesomeric Hyperconjugation and Resonance
Heterolytic cleavage of CH₃CH₂CH(CH₃)CH₂Cl at CH₂Cl forms CH₃CH₂CH(CH₃)CH₂⁺ (primary), but a hydride shift forms CH₃CH₂C⁺(CH₃)CH₃ (tertiary), stabilized by the +I effect of three alkyl groups.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Electronic Effects - Inductive Mesomeric Hyperconjugation and Resonance
Tertiary carbocations are more stable due to hyperconjugation and inductive effects. (CH₃)₃C⁺ (tertiary) is more stable than primary or secondary ones.
Ref: NCERT Class 11 Chemistry > Chapter 8: Organic Chemistry - Some Basic Principles and Techniques > Topic: Electronic Effects - Inductive Mesomeric Hyperconjugation and Resonance
