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Moles = 2.24/22.4 = 0.1 mol. Molar mass = 3.2/0.1 = 32 g/mol.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent
Reaction: 2Mg + O₂ → 2MgO. Moles of Mg = 0.5 mol; needs 0.25 mol O₂ (8 g). With 75% efficiency, total O₂ = 8 / 0.75 ≈ 10.67 g.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent
Total mass = 5.6 + 44.4 = 50 g. Mass % = (5.6/50) × 100 = 11.2%.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent
Moles of HNO₃ = 9.75/63 ≈ 0.1548 mol. Volume = 0.25 L. Molarity = 0.1548/0.25 ≈ 0.619 M.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent
Mass of 1 L solution = 1000 × 1.05 = 1050 g. Mass of HNO₃ = 1.5 × 63 = 94.5 g. Mass of water = 955.5 g = 0.9555 kg. Molality = 1.5 / 0.9555 ≈ 1.57 m.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent
M₁V₁ = M₂V₂. 0.3 × 100 = M₂ × (100 + 400). M₂ = (0.3 × 100)/500 = 0.06 M.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent
Reaction: N₂ + 3H₂ → 2NH₃. Moles of H₂ = 3 mol. 1 mol N₂ needs 3 mol H₂; 3 mol H₂ needs 1 mol N₂ = 28 g.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent
Reaction: 2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O. Moles of C₄H₁₀ ≈ 0.1724 mol. 2 mol produce 8 mol CO₂; 0.1724 mol produce ≈ 0.6896 mol. Volume = 0.6896 × 22.4 ≈ 15.45 L.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent
Reaction: 2SO₂ + O₂ → 2SO₃. Moles: SO₂ = 0.25 mol, O₂ = 0.25 mol. 0.25 mol SO₂ produces 0.25 mol SO₃ = 0.25 × 80 = 20 g.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent
Moles of HCl = 7.3/36.5 = 0.2 mol. Volume = 0.2 L. Molarity = 0.2/0.2 = 1 M.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent
Moles = 5.6/22.4 = 0.25 mol. Molar mass = 8/0.25 = 32 g/mol.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent
Reaction: Fe₂O₃ + 3CO → 2Fe + 3CO₂. Moles of Fe₂O₃ = 16/160 = 0.1 mol. 0.1 mol Fe₂O₃ produces 0.2 mol Fe = 0.2 × 56 = 11.2 g.
Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Stoichiometry and Stoichiometric Calculations and Limiting Reagent
