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Rigid Body Motion and Equilibrium

This category covers the motion and equilibrium of rigid bodies under various forces. Practice problems help you understand how to determine balance and stability in rotating objects.

26 questions

A 1kg mass rotates in a circle of radius 0.9m with a speed of 6m/s. What is its angular momentum about the center?

L = mvr. m = 1kg, v = 6m/s, r = 0.9m. L = 1×6×0.9 = 5.4kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.4 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A hollow cylinder of mass 2kg and radius 0.8m has an angular momentum of 16kg m2/s. What is its angular velocity?

I = MR2 = 2×(0.8)2 = 1.28kg m2. ω = LI = 161.28 = 12.5rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 12.5 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A solid sphere of mass 1kg and radius 0.5m has a kinetic energy of 5J. What is its angular speed?

I = 25MR2 = 25×1×(0.5)2 = 0.1kg m2. K = 12Iω2⇒5 = 12×0.1×ω2⇒10 = 0.1ω2⇒ω2 = 100⇒ω = 10rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 10 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

Which factor does not affect the moment of inertia of a rigid body?

Moment of inertia (I = ∑miri2) depends on mass and its distribution about the axis, not on angular velocity, which affects motion but not I. As per NCERT, applying relevant law/formula with correct units and sign convention leads to Angular velocity. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A solid cylinder of mass 2kg and radius 0.1m rotates about its axis at 20rad/s. What is its rotational kinetic energy?

I = 12MR2 = 12×2×(0.1)2 = 0.01kg m2. K = 12Iω2 = 12×0.01×(20)2 = 0.005×400 = 2J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.0 J. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A solid cylinder of mass 5kg and radius 0.5m has an angular momentum of 12.5kg m2/s. What is its angular velocity?

I = 12MR2 = 12×5×(0.5)2 = 0.625kg m2. ω = LI = 12.50.625 = 20rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 20 rad/s. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A 1kg mass rotates in a circle of radius 0.8m with a speed of 5m/s. What is its angular momentum about the center?

L = mvr. m = 1kg, v = 5m/s, r = 0.8m. L = 1×5×0.8 = 4kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 4.0 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A thin ring of mass 2kg and radius 0.7m rolls without slipping with a linear speed of 3.5m/s. What is its angular veloci

v = ωr. v = 3.5m/s, r = 0.7m. ω = vr = 3.50.7 = 5rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.

A thin ring of mass 2kg and radius 0.4m has a kinetic energy of 8J. What is its angular speed?

I = MR2 = 2×(0.4)2 = 0.32kg m2. K = 12Iω2⇒8 = 12×0.32×ω2⇒16 = 0.32ω2⇒ω2 = 50⇒ω = 50≈7.07rad/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 7 rad/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.