Latest questions in this category.
The nuclear force becomes strongly repulsive at distances less than 0.8 fm, preventing nucleons from collapsing into each other, as shown in the potential energy plot.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Electric Charges and Fields and Electrostatic Potential, Topic: Electric field, potential and capacitance concepts.
Given: A copper wire of length 2 m and cross-sectional area 2 × 10â»â¶ m² carries a current of 2 A . If the number density of free electrons in copper is 8.5 × 10²⸠m^{-3 and e = 1.6 × 10â»Â¹â¹ C, what is the drift speed of the electrons? These values define the system as per NCERT data. Formula: Drift speed is given by v_d = I/n e A. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Given: I = 2 A, n = 8.5 × 10²⸠m^{-3, e = 1.6 × 10â»Â¹â¹ C, A = 2 × 10â»â¶ m² . Substitute: v_d = frac28.5 × 10²⸠× 1.6 × 10â»Â¹â¹ × 2 × 10â»â¶. Calculate: v_d = 2/2.72 × 10â´= 7.35 × 10â»âµ m/s . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Current Electricity, Topic: Resistivity, temperature dependence and circuit analysis.
Given: The threshold wavelength for a metal is 500 nm . What is the work function of the metal in eV? (Take h = 6.63 × 10â»Â³â´ J s, c = 3 × 10⸠m/s, 1 eV = 1.6 × 10â»Â¹â¹ J ) These values define the system as per NCERT data. Formula: Threshold frequency v_0 = c/lambda_0 = frac3 × 10â¸âµâ°â° × 10â»â¹= 6 × 10¹ⴠHz. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: phi_0 = h v_0 = 6.63 × 10â»Â³â´ × 6 × 10¹â´= 3.978 × 10â»Â¹â¹ J . phi_0 = frac3.978 × 10â»Â¹â¹Â¹.6 × 10â»Â¹â¹ approx 2.49 eV . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Oscillations and Waves, Topic: SHM, wave motion and superposition.
The document states that infrared waves are produced by hot bodies and molecules, often referred to as heat waves. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Oscillations and Waves, Topic: SHM, wave motion and superposition.
Given: A concave lens of focal length 25 cm forms an image 10 cm from the lens. What is the object distance? These values define the system as per NCERT data. Formula: Focal length: f = -25 cm (concave lens). This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Image distance: v = -10 cm (virtual image). Lens formula: 1/v - 1/u = 1/f . 1/-10 - 1/u = 1/-25 Rightarrow 1/u = 1/-10 - 1/-25 = -5 + 2/50 = -3/50 . u = -50/3 approx -16.67 cm . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Ray Optics and Optical Instruments and Wave Optics, Topic: Refraction, lenses and interference/diffraction.
Given: A circular loop of radius 0.13 m with 20 turns carries a current of 3.5 A . What is the magnetic field at the nter? ( μ_0 = 4 Ï€ × 10â»â· T m/A ) These values define the system as per NCERT data. Formula: Magnetic field B = μ_0 N I/2 R. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: B = frac4 Ï€ × 10â»â· × 20 × 3.52 × 0.13 = frac28 Ï€ × 10â»â¶â°.26 = 1.0769 Ï€ × 10â»â´ approx 3.38 × 10â»â´ T . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Moving Charges and Magnetism and Magnetism and Matter, Topic: Magnetic field due to current loop, solenoid and magnetic dipole moment. Page number should be added only after verification from the.
Given: A particle rotates about a fixed axis at a radius of 0.6 m with a linear speed of 7.2 m/s . What is its angular velocity? These values define the system as per NCERT data. Formula: v = omega r. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: v = 7.2 m/s, r = 0.6 m . omega = v/r = 7.2/0.6 = 12 rad/s . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Units and Measurements and Physical World, Topic: Dimensional analysis and fundamental principles.
Insulators have high resistivity ( 10¹Ⱐto 10¹â¹Î© m ) or low conductivity ( 10â»Â¹Â¹ to 10â»Â¹â¹ S m^{-1 ), preventing significant current flow. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Current Electricity, Topic: Resistivity, temperature dependence and circuit analysis.
The ground state is the lowest energy state, where the electron is in the orbit with n = 1, having an energy of -13.6 eV. This follows from NCERT principle where the relation explains the outcome clearly for students in simple steps.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Laws of Motion, Work Energy Power, Gravitation and System of Particles, Topic: Newton's laws, work-energy theorem and rotational dynamics.
Given: A photon of wavelength 300 nm is incident on a metal. What is its energy in eV? (Take h c = 1240 eV nm ) These values define the system as per NCERT data. Formula: Energy E = h c/lambda. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: E = 1240/300 approx 4.13 eV . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Oscillations and Waves, Topic: SHM, wave motion and superposition.
Given: A shell of mass 0.01 kg is fired from a gun of mass 50 kg with a muzzle speed of 100 m/s . What is the recoil speed of the gun? These values define the system as per NCERT data. Formula: Before firing: p_{initial = 0. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: By conservation of momentum, total momentum before and after firing is zero. . After firing: m_{shell v_{shell + m_{gun v_{gun = 0 . Substitute: 0.01 × 100 + 50 × v_{gun = 0 . 1 + 50 v_{gun = 0 Rightarrow v_{gun = -1/50 = -0.02 m/s . Recoil speed (magnitude) = 0.02 m/s . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Moving Charges and Magnetism and Magnetism and Matter, Topic: Magnetic field due to current loop, solenoid and magnetic dipole moment. Page number should be added only after verification from the.
Given: A solenoid with mutual inductance 0.22 H has a current change of 7 A/s in the primary coil. What is the induced emf in the secondary coil? These values define the system as per NCERT data. Formula: varepsilon = M dI/dt = 0.22 × 7 = 1.54 V .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10â»âµ, 236 J kgâ»Â¹ Kâ»Â¹, CH₃CHâ‚‚NHâ‚‚ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Moving Charges and Magnetism and Magnetism and Matter, Topic: Magnetic field due to current loop, solenoid and magnetic dipole moment. Page number should be added only after verification from the.
