Practice question

Given: A ll of emf 9 V and internal resistance 3 Ω is connected to a 6 Ω resistor. What is the current in the circuit? These values define the system as per NCERT data. Formula: Total resistance: R_{total = 6 + 3 = 9 Ω. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Current: I = fracvarepsilonR_{total = 9/9 = 1 A . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.