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Mole Concept and Molar Masses and Percentage Composition

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29 questions

A 0.98 g sample of a hydrocarbon produces 3.08 g of CO₂ and 1.26 g of H₂O on complete combustion. What is its molecular

Mass of C ≈ 0.84 g; mass of H = 0.14 g. Total = 0.98 g. Moles: C = 0.07, H = 0.14; ratio = 1 : 2; empirical formula = CH₂, mass = 14 g/mol. n = 98/14 = 7; molecular formula = C₇H₁₄.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Mole Concept and Molar Masses and Percentage Composition

A 10 L sample of a gas at STP weighs 11.6 g and contains only C and H. If it produces 3.38 g CO₂ on burning, what is its

Moles of gas ≈ 0.446 mol; molar mass ≈ 26 g/mol. Mass of C ≈ 0.922 g; C atoms per molecule adjusted to 1 (or 2 for C₂H₂). Molecular formula consistent with C₂H₂ (molar mass 26).

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Mole Concept and Molar Masses and Percentage Composition

A 0.54 g sample of a hydrocarbon produces 1.76 g of CO₂ and 0.36 g of H₂O on complete combustion. If its molar mass is 5

Mass of C ≈ 0.48 g; mass of H = 0.04 g. Moles: C = 0.04, H = 0.04; ratio = 1 : 1; empirical formula = CH, mass = 13 g/mol. n ≈ 4; molecular formula = C₄H₄.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Mole Concept and Molar Masses and Percentage Composition

A 0.84 g sample of a hydrocarbon produces 2.64 g of CO₂ and 1.08 g of H₂O on complete combustion. What is its molecular

Mass of C ≈ 0.72 g; mass of H = 0.12 g. Total = 0.84 g. Moles: C = 0.06, H = 0.12; ratio = 1 : 2; empirical formula = CH₂, mass = 14 g/mol. n = 84/14 = 6; molecular formula = C₆H₁₂.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Mole Concept and Molar Masses and Percentage Composition

A 0.42 g sample of a hydrocarbon produces 1.32 g of CO₂ and 0.54 g of H₂O on complete combustion. What is its molecular

Mass of C ≈ 0.36 g; mass of H = 0.06 g. Total = 0.42 g. Moles: C = 0.03, H = 0.06; ratio = 1 : 2; empirical formula = CH₂, mass = 14 g/mol. n = 42/14 = 3; molecular formula = C₃H₆.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Mole Concept and Molar Masses and Percentage Composition

How many liters of CO₂ at STP are produced when 10 g of CaCO₃ reacts with excess HCl with 80% efficiency? (Molar mass: C

Reaction: CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O. Moles of CaCO₃ = 0.1 mol; theoretical CO₂ = 0.1 mol. Actual CO₂ = 0.1 × 0.8 = 0.08 mol; volume = 0.08 × 22.4 = 1.792 L.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Mole Concept and Molar Masses and Percentage Composition

A compound contains 26.67% carbon, 2.22% hydrogen, and 71.11% oxygen by mass. If its molar mass is 90 g/mol, what is its

For 100 g: C = 26.67 g, H = 2.22 g, O = 71.11 g. Moles: C ≈ 2.22, H = 2.22, O ≈ 4.44. Ratio = 1 : 1 : 2; empirical formula = CHO₂, mass = 45 g/mol. n = 90/45 = 2; molecular formula = C₂H₂O₄.

Ref: NCERT Class 11 Chemistry > Chapter 1: Some Basic Concepts of Chemistry > Topic: Mole Concept and Molar Masses and Percentage Composition