Practice question
Question
How many liters of CO₂ at STP are produced when 10 g of CaCO₃ reacts with excess HCl with 80% efficiency? (Molar mass: CaCO₃ = 100 g/mol)
Explanation
Reaction: CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O. Moles of CaCO₃ = 0.1 mol; theoretical CO₂ = 0.1 mol. Actual CO₂ = 0.1 × 0.8 = 0.08 mol; volume = 0.08 × 22.4 = 1.792 L.
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