How many electrons in an atom can have n = 3 and l = 2?
For l=2 (d), orbitals = 5. Electrons = 10.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
Shapes of Orbitals - s p d f and Nodes and Radial Probability
Latest questions in this category.
Filter questions
The energy required to eject an electron from a metal is 4.5 × 10⁻¹⁹ J. If light of frequency 8.0 × 10¹⁴ Hz is used, wha
E ≈ 5.301×10⁻¹⁹ J. KE ≈ 8.008×10⁻²⁰ J.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
Which series of spectral lines in a hydrogen atom lies in the visible region?
The Balmer series lies in the visible region.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
The ionization energy of Li²⁺ is 122.4 eV. What is the wavelength of light required to excite an electron from n = 1 to
ΔE = 108.8 eV. λ ≈ 11.42 nm.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
The number of electrons in an atom with quantum numbers n = 4, l = 1, mₗ = 0 is:
One specific 4p orbital holds 2 electrons.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
The number of spectral lines produced when an electron in a hydrogen atom falls from n = 5 to n = 2 is:
Transitions: 5→2, 5→3→2, 5→4→2, 4→2, 3→2. Total = 5.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
The angular momentum of an electron in the fourth orbit of a hydrogen atom is 4.22 × 10⁻³⁴ J s. What is its energy in eV
n=4. E₄ = -13.6/16 = -0.85 eV.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
The ratio of the radii of the fourth orbit of H to the third orbit of Be³⁺ is: (r₁ for H = 5.29 × 10⁻¹¹ m)
r₄(H)/r₃(Be³⁺) ≈ 7.11.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
The number of spectral lines in the Brackett series when an electron falls from n = 7 to n = 4 in a hydrogen atom is:
Transitions: 7→4, 7→5→4, 7→6→4, 6→4, 5→4. Total = 5.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
Which orbital is represented by the quantum numbers n = 3, l = 1?
n=3, l=1 corresponds to 3p orbital.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
The uncertainty in the position of an electron is 1.0 × 10⁻¹⁰ m. What is the minimum uncertainty in its velocity? (h = 6
Δv ≥ h/(4π m Δx) ≈ 5.8×10⁵ m s⁻¹.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
A metal has a threshold frequency of 4.8 × 10¹⁴ Hz. What is the kinetic energy of an electron ejected by light of freque
W₀ = hν₀. KE = h(ν - ν₀) ≈ 1.590×10⁻¹⁹ J.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability