What is the oxidation number of carbon in CH₄?
Let C = x. H = +1. Equation: x + 4(+1) = 0, x + 4 = 0, x = -4.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
This category focuses on electrode potential, the electrochemical series, and the operation of galvanic cells. Learn how these concepts relate to electrochemistry and solve problems involving cell potentials and reactions.
Let C = x. H = +1. Equation: x + 4(+1) = 0, x + 4 = 0, x = -4.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
C in CO₂: +4. In CH₂O: x + 2(+1) + (-2) = 0, x = 0, which is lower.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
In S₈ + 8O₂ → 8SO₂, S (0) is oxidized to +4, and O (0) is reduced to -2.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
O (-1 in H₂O₂) becomes -2 in H₂O, gaining electrons.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
Oxidation involves electron loss. S (-2 in H₂S) becomes 0 in S, losing electrons.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
Let S = x. H = +1. Equation: 2(+1) + x = 0, 2 + x = 0, x = -2.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
C (+3 in C₂O₄²−) to +4 in CO₂ is oxidized; Mn (+7 to +2) is reduced.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
KI (I: -1 to 0 in I₂) loses electrons, reducing Br₂ (0 to -1).
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
Let Os = x. O = -2. Equation: x + 4(-2) = 0, x - 8 = 0, x = +8.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
In 2Al + 3Cl₂ → 2AlCl₃, Al (0) loses electrons to become Al₃+ (+3).
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
Br₂ (0) is reduced to -1 in NaBr and oxidized to +5 in NaBrO₃, acting as its own oxidizing agent.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells
In 4Na + O₂ → 2Na₂O, Na gains oxygen to form Na₂O, an oxidation process.
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Electrode Potential and Electrochemical Series and Galvanic Cells