Practice question
Question
A 0.84 g sample of a hydrocarbon produces 2.64 g of CO₂ and 1.08 g of H₂O on complete combustion. What is its molecular formula if its molar mass is 84 g/mol? (Atomic masses: C = 12, H = 1, O = 16)
Explanation
Mass of C ≈ 0.72 g; mass of H = 0.12 g. Total = 0.84 g. Moles: C = 0.06, H = 0.12; ratio = 1 : 2; empirical formula = CH₂, mass = 14 g/mol. n = 84/14 = 6; molecular formula = C₆H₁₂.
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