NEET MOCK TEST 17

CHEMISTRY

Which of the following amines has the nitrogen atom with the greatest lone pair availability for protonation?

In (CH₃)2NH, the lone pair is enhanced by the inductive effect of two methyl groups and not delocalized (unlike aniline), making it highly available for protonation.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII), Chapter: Chemical Bonding (Latest NCERT 2026-27), Topic: Hybridization of nitrogen in CH₃NH₂, sp³ hybridization and pyramidal geometry

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CHEMISTRY

Which complex shows geometrical isomerism?

[Co(NH₃)4Cl₂]+ is octahedral and can form cis and trans isomers due to two Cl^- ligands. This follows from latest NCERT 2026-27 principle explaining the concept clearly for NEET students in simple steps as per rationalized syllabus.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

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CHEMISTRY

Which complex has an octahedral coordination polyhedron?

[Fe(CN)6]^{3- has 6 CN^- ligands around Fe³⁺, forming an octahedral geometry, unlike the tetrahedral or square planar options. This follows from latest NCERT 2026-27 principle explaining the concept clearly for NEET students in simple steps as per rationalized syllabus.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

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CHEMISTRY

What is the approximate ratio of the radius of an atom to its nucleus?

Rutherford’s model states the atomic radius is about 10⁻¹⁰m and the nuclear radius is 10⁻¹⁵m, giving a ratio of 10⁻¹⁰/ 10⁻¹⁵= __10POW₅__. This follows from latest NCERT 2026-27 principle explaining the concept clearly for NEET students in simple steps as per rationalized syllabus.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

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CHEMISTRY

What is the formal charge on the carbon atom in the CO₃²- ion in one of its resonance structures?

In one resonance structure of CO₃²-, carbon has 1 double bond (4 electrons) and 2 single bonds (4 electrons). Formal charge = 4 - 0 - 1/2 × 8 = 0. This follows from latest NCERT 2026-27 principle explaining the concept clearly for NEET students in simple steps as per rationalized syllabus.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII), Chapter: Electrochemistry (Latest NCERT 2026-27), Topic: Faraday's laws, charge required to reduce Al³⁺, 3F = 3 × 96500 C

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PHYSICS

A uniform field E = 5 × 10³N/C is along the x-axis. What is the net flux through a cube of side 30 cm with faces paralle

Given: A uniform field E = 5 × 10³N/C is along the x-axis. What is the net flux through a cube of side 30 cm with faces parallel to coordinate planes? Formula: Flux through face at x = 0 : phi = E × A = 5 × 10³ × (0.3)² = 450 Nm²/C (inward). Substitution & Calculation: Flux through face at x = 0.3 : 450 Nm²/C (outward). Net flux: 450 - 450 = 0 Nm²/C (no charge enclosed). Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Physics Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII, continuing as per NCERT advisory for 2026-27),Topic: Fundamental laws, definitions and applications as per latest NCERT. The section explains governing laws, formulas like μ₀ = 4π.

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CHEMISTRY

Calculate the boiling point elevation of a solution containing 7.2 g of glucose ( C₆H₁₂O₆ ) in 300 g of water. ( K_b = 0

Given: Calculate the boiling point elevation of a solution containing 7.2 g of glucose ( C₆H₁₂O₆ ) in 300 g of water. ( K_b = 0.52 K kg/mol, Molar mass of glucose = 180 g/mol ) Formula: Moles of glucose = 7.2/180 = 0.04 mol. Substitution & Calculation: Molality = 0.04/0.3 = 0.133 mol/kg . Δ T_b = 0.52 × 0.133 = 0.069 K . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII), Chapter: Solutions (Latest NCERT 2026-27), Topic: Colligative properties, ΔT_b = K_b·m, urea NH₂CONH₂ example

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PHYSICS

What is the mass defect of a nucleus with binding energy 102.3 MeV ? (Given 1 u = 931.5 MeV/c² )

Given: What is the mass defect of a nucleus with binding energy 102.3 MeV ? (Given 1 u = 931.5 MeV/c² ) Formula: Δ M = E_b/c². Substitution & Calculation: Δ M = 102.3/931.5 approx 0.11 u . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Physics Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII, continuing as per NCERT advisory for 2026-27),Topic: Fundamental laws, definitions and applications as per latest NCERT. The section explains governing laws, formulas like μ₀ = 4π.

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CHEMISTRY

The initial rate of a reaction is 1.8 × 10⁻³mol L^{-1 s^{-1 when [A] = 0.2 M and [B] = 0.3 M. If the rate law is Rate =

Given: The initial rate of a reaction is 1.8 × 10⁻³mol L^{-1 s^{-1 when [A] = 0.2 M and [B] = 0.3 M. If the rate law is Rate = k[A]²[B], what is k in L² mol^{-2 s^{-1 ? Formula: k = fracRate[A]²[B] = frac1.8 × 10⁻³(0.2)² × 0.3 = frac1.8 × 10⁻³⁰.012 = 0.15 .. Substitution: Substituting given values into formula as per NCERT 2026-27 method. Calculation: Simplifying step by step with proper SI units like m/s², J kg⁻¹ K⁻¹, 10⁻⁵, A m⁻¹ etc. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

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CHEMISTRY

What is the potential of a hydrogen electrode in a solution with pH = 5 at 298 K, given E⁰ = 0 V ?

Given: What is the potential of a hydrogen electrode in a solution with pH = 5 at 298 K, given E⁰ = 0 V ? Formula: For H+ + e- -> 1/2 H₂, E = E⁰ - 0.059/1 log frac1[H^+]. Substitution & Calculation: [H^+] = 10⁻⁵, E = 0 - 0.059 × 5 = -0.295 V . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

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PHYSICS

The de Broglie wavelength of a particle of mass 2.0 × 10⁻³⁰kg moving at 1.5 × 10⁶m/s is:

Given: The de Broglie wavelength of a particle of mass 2.0 × 10⁻³⁰kg moving at 1.5 × 10⁶m/s is: Formula: p = m v = 2.0 × 10⁻³⁰ × 1.5 × 10⁶= 3.0 × 10⁻²⁴kg m/s. Substitution & Calculation: lambda = h/p = frac6.63 × 10⁻³⁴³.0 × 10⁻²⁴= 2.21 × 10⁻¹⁰m = 0.221 nm . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Physics Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII, continuing as per NCERT advisory for 2026-27),Topic: Fundamental laws, definitions and applications as per latest NCERT. The section explains governing laws, formulas like μ₀ = 4π.

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PHYSICS

A spring-mass system has m = 2.25 kg, k = 900 N/m . What is its period?

Given: A spring-mass system has m = 2.25 kg, k = 900 N/m . What is its period? Formula: Period: T = 2π √m/k = 2π √2.25/900 = 2π √0.0025 = 2π × 0.05 = 0.314 s .. Substitution: Substituting given values into formula as per NCERT 2026-27 method. Calculation: Simplifying step by step with proper SI units like m/s², J kg⁻¹ K⁻¹, 10⁻⁵, A m⁻¹ etc. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Physics Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII, continuing as per NCERT advisory for 2026-27),Topic: Fundamental laws, definitions and applications as per latest NCERT. The section explains governing laws, formulas like μ₀ = 4π.

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