Practice question
Question
What is the mass defect of a nucleus with binding energy 102.3 MeV ? (Given 1 u = 931.5 MeV/c² )
Explanation
Given:
What is the mass defect of a nucleus with binding energy 102.3 MeV ? (Given 1 u = 931.5 MeV/c² )
Formula:
Δ M = E_b/c².
Substitution & Calculation:
Δ M = 102.3/931.5 approx 0.11 u .
Final Result:
The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
Discussion
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