NEET MOCK TEST 15

PHYSICS

A uniform square plate of side 6 m and mass 9 kg has one corner at (2, 2) along the x- and y-axes. What is the position

Given: A uniform square plate of side 6 m and mass 9 kg has one corner at (2, 2) along the x- and y-axes. What is the position of its nter of mass? These values define the system as per NCERT data. Formula: CM: X = 2 + 6/2 = 5, Y = 2 + 6/2 = 5. This is standard NCERT relation. Substitution & Calculation: For a uniform square, the nter of mass is at the ntroid. Vertices: (2, 2), (8, 2), (2, 8), (8, 8) . . Position: (5, 5) m . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Relevant Physics topic covering fundamental principles,

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CHEMISTRY

Which of the following is the correct order of increasing basicity in the gas phase?

In the gas phase, basicity increases with alkyl substitution due to the inductive effect: NH₃ < CH₃NH₂ < (CH₃)2NH < (CH₃)3N, unaffected by solvation. This follows from NCERT principle where relation explains outcome clearly for students.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Chemical Bonding, Topic: Hybridization of nitrogen in CH₃NH₂, sp³ hybridization, pyramidal geometry.

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CHEMISTRY

Which complex has the highest number of unpaired electrons?

[Fe(H₂O)6]^{3+ (Fe³⁺, d⁵ ) with weak field H₂O is high spin ( t_{2g³ e_g² ), with 5 unpaired electrons, the highest among the options. This follows from NCERT principle where relation explains outcome clearly for students.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.

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CHEMISTRY

Which complex has a trigonal bipyramidal geometry?

[Fe(CO)5] has 5 CO ligands around Fe(0), adopting a trigonal bipyramidal geometry, unlike the tetrahedral, square planar, or octahedral options. This follows from NCERT principle where relation explains outcome clearly for students.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.

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CHEMISTRY

The oxidation state of sulfur in SO_3 is:

Given: The oxidation state of sulfur in SO_3 is: These values define the system as per NCERT data. Formula: In SO_3, O is -2, so 3(-2) + S = 0, S = +6, as sulfur shares electrons with three oxygen atoms.. This is standard NCERT relation. Substitution & Calculation: Substituting values and simplifying step by step as per NCERT method. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.

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CHEMISTRY

The initial rate of a reaction is 1.2 × 10⁻³mol L^{-1 s^{-1 when [A] = 0.2 M and [B] = 0.3 M. If the order is 1 with res

Given: The initial rate of a reaction is 1.2 × 10⁻³mol L^{-1 s^{-1 when [A] = 0.2 M and [B] = 0.3 M. If the order is 1 with respect to A and 1 with respect to B, what is k in L mol^{-1 s^{-1 ? These values define the system as per NCERT data. Formula: k = fracRate[A][B] = frac1.2 × 10⁻³⁰.2 × 0.3 = 0.02 .. This is standard NCERT relation. Substitution & Calculation: Substituting values and simplifying step by step as per NCERT method. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.

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CHEMISTRY

A solution of two volatile liquids A and B has a total vapor pressure of 290 mm Hg. If the vapor pressure of pure A is 4

Given: A solution of two volatile liquids A and B has a total vapor pressure of 290 mm Hg. If the vapor pressure of pure A is 450 mm Hg and that of pure B is 150 mm Hg, what is the mole fraction of A in the solution? These values define the system as per NCERT data. Formula: Using Raoult's law: p_{total = x_A p_A⁰ + (1 - x_A) p_B⁰. This is standard NCERT relation. Substitution & Calculation: 290 = x_A · 450 + (1 - x_A) · 150 . 290 = 450 x_A + 150 - 150 x_A . 140 = 300 x_A, x_A = 0.467 . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.

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CHEMISTRY

What is the molarity of a solution prepared by dissolving 4 g of NaOH in water to make 200 mL of solution? (Molar mass o

Given: What is the molarity of a solution prepared by dissolving 4 g of NaOH in water to make 200 mL of solution? (Molar mass of NaOH = 40 g/mol) These values define the system as per NCERT data. Formula: Moles = 4 / 40 = 0.1 mol. This is standard NCERT relation. Substitution & Calculation: Volume = 0.2 L. Molarity = 0.1 / 0.2 = 0.5 M. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.

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PHYSICS

A 7 μF capacitor is charged to 400 V . What is the energy stored in it?

Given: A 7 μF capacitor is charged to 400 V . What is the energy stored in it? These values define the system as per NCERT data. Formula: U = 1/2 C V² = 1/2 × 7 × 10⁻⁶ × (400)². This is standard NCERT relation. Substitution & Calculation: U = 1/2 × 7 × 10⁻⁶ × 160000 = 0.56 J . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Relevant Physics topic covering fundamental principles,

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PHYSICS

A 8.5 kg block on a horizontal surface ( μ_k = 0.25 ) is pulled by a 4.5 kg mass over a pulley. A 15 N force opposes the

Given: A 8.5 kg block on a horizontal surface ( μ_k = 0.25 ) is pulled by a 4.5 kg mass over a pulley. A 15 N force opposes the 8.5 kg block. What is the acceleration? (Take g = 10 m/s² ) These values define the system as per NCERT data. Formula: For 4.5 kg : 4.5g - T = 4.5a Rightarrow 45 - T = 4.5a. This is standard NCERT relation. Substitution & Calculation: For 8.5 kg : T - f_k - 15 = 8.5a . Normal: N = mg = 8.5 × 10 = 85 N . Friction: f_k = 0.25 × 85 = 21.25 N . Net force: T - 21.25 - 15 = 8.5a Rightarrow T - 36.25 = 8.5a . Solve: 45 - T = 4.5a, T - 36.25 = 8.5a . Substitute: 45 - (8.5a + 36.25) = 4.5a Rightarrow 45 - 36.25 - 8.5a = 4.5a Rightarrow 8.75 = 13a . a = 8.75/13 approx 0.67 m/s² . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Relevant Physics topic covering fundamental principles,

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PHYSICS

A wheel with 10 spokes of 0.7 m each rotates at 60 rpm in a 0.5 T field. What is the induced emf?

Given: A wheel with 10 spokes of 0.7 m each rotates at 60 rpm in a 0.5 T field. What is the induced emf? These values define the system as per NCERT data. Formula: omega = 2π × 60/60 = 2π rad/s. This is standard NCERT relation. Substitution & Calculation: varepsilon = 1/2 B omega R² = 1/2 × 0.5 × 2π × (0.7)² = 0.7697 V approx 0.77 V . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Relevant Physics topic covering fundamental principles,

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PHYSICS

A wheel with 6 spokes of 0.6 m each rotates at 45 rpm in a 0.5 T field. What is the induced emf?

Given: A wheel with 6 spokes of 0.6 m each rotates at 45 rpm in a 0.5 T field. What is the induced emf? These values define the system as per NCERT data. Formula: omega = 2π × 45/60 = 1.5π rad/s. This is standard NCERT relation. Substitution & Calculation: varepsilon = 1/2 B omega R² = 1/2 × 0.5 × 1.5π × (0.6)² = 0.8478 V approx 0.85 V . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.

Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Relevant Physics topic covering fundamental principles,

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