Practice question

Given: A 7 μF capacitor is charged to 400 V . What is the energy stored in it? These values define the system as per NCERT data. Formula: U = 1/2 C V² = 1/2 × 7 × 10⁻⁶ × (400)². This is standard NCERT relation. Substitution & Calculation: U = 1/2 × 7 × 10⁻⁶ × 160000 = 0.56 J . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.