NEET Mock Test 13 is a practice test set for students preparing for the NEET medical entrance exam. It brings together questions across the core NEET subjects so you can test your recall, work on timing, and see which topics still need attention. Attempt the questions online and review the answers once you finish.
Co³⁺ with 4 NH₃ and 2 H₂O (neutral) forms [Co(NH₃)4(H₂O)2]^{3+, balanced by 3 Cl^-, giving [Co(NH₃)4(H₂O)2]Cl₃ . This follows from NCERT principle where relation explains outcome clearly for students.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.
[Co(NH₃)5(SCN)]^{2+ has the ambidentate ligand SCN^-, which can bind via S or N, showing linkage isomerism. This follows from NCERT principle where relation explains outcome clearly for students.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.
[Au(CN)2]^{- is used in gold electroplating for smooth deposition, unlike the others. This follows from NCERT principle where relation explains outcome clearly for students.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.
Given: The initial rate of a reaction is 1.6 × 10⁻³mol L^{-1 s^{-1 when [A] = 0.4 M and [B] = 0.1 M. If the rate law is Rate = k[A]², what is k in L mol^{-1 s^{-1 ? These values define the system as per NCERT data. Formula: k = fracRate[A]² = frac1.6 × 10⁻³(0.4)² = frac1.6 × 10⁻³⁰.16 = 0.01 .. This is standard NCERT relation. Substitution & Calculation: Substituting values and simplifying step by step as per NCERT method. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.
Given: A gaseous reaction follows Rate = k p_A² with k = 0.1 atm^{-1 s^{-1 and p_A = 0.6 atm . What is the rate in atm s^{-1 ? These values define the system as per NCERT data. Formula: Rate = k p_A² = 0.1 × (0.6)² = 0.1 × 0.36 = 0.036 .. This is standard NCERT relation. Substitution & Calculation: Substituting values and simplifying step by step as per NCERT method. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.
Given: What is the molarity of a solution prepared by dissolving 4 g of NaOH in 500 mL of solution? (Molar mass: NaOH = 40 g/mol ) These values define the system as per NCERT data. Formula: Moles of NaOH = 4/40 = 0.1 mol. This is standard NCERT relation. Substitution & Calculation: Volume in liters = 500/1000 = 0.5 L . Molarity = 0.1/0.5 = 0.2 M . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.
Given: A stationary wave on a string fixed at both ends has a frequency of 150 Hz and a wave speed of 45 m/s. What is the wavelength? These values define the system as per NCERT data. Formula: Wavelength: lambda = v/v = 45/150 = 0.3 m .. This is standard NCERT relation. Substitution & Calculation: Substituting values and simplifying step by step as per NCERT method. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Relevant Physics topic covering fundamental principles,
Given: The work function of a metal is 3.0 eV . Light of frequency 8.0 × 10¹⁴Hz is incident on it. What is the stopping potential? (Take h = 6.63 × 10⁻³⁴J s, e = 1.6 × 10⁻¹⁹C ) These values define the system as per NCERT data. Formula: E = h v = 6.63 × 10⁻³⁴ × 8.0 × 10¹⁴= 5.304 × 10⁻¹⁹J. This is standard NCERT relation. Substitution & Calculation: E = frac5.304 × 10⁻¹⁹¹.6 × 10⁻¹⁹approx 3.315 eV . K_{max = E - phi_0 = 3.315 - 3.0 = 0.315 eV . V_0 = fracK_{maxe = 0.315 V . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Dual Nature of Radiation and Matter, Topic: Photoelectric effect, stopping potential, Kmax = eV₀, work function and photon energy. The section explains definitions, governing laws, formulas like μ₀ = 4π × 10⁻⁷ T·m/A, units and illustrative examples.
Given: A spring-mass system has m = 0.6 kg, k = 240 N/m . If displaced by 7 cm, what is the total energy? These values define the system as per NCERT data. Formula: Total energy: E = 1/2 k A². This is standard NCERT relation. Substitution & Calculation: A = 0.07 m, k = 240 N/m . E = 0.5 × 240 × (0.07)² = 0.5 × 240 × 0.0049 = 0.588 J . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Gravitation, Topic: Total energy of satellite E = -GMm/2r, orbital energy at 5R_E and negative sign. The section explains definitions, governing laws, formulas like μ₀ = 4π × 10⁻⁷ T·m/A, units and illustrative examples.
Given: A mercury barometer shows a height of 75 cm at sea level. What is the atmospheric pressure? ( rho = 13.6 × 10³kg/m³, g = 10 m/s² ) These values define the system as per NCERT data. Formula: P_a = rho g h. This is standard NCERT relation. Substitution & Calculation: rho = 13.6 × 10³kg/m³, g = 10 m/s², h = 0.75 m . P_a = 13.6 × 10³ × 10 × 0.75 = 1.02 × 10⁵Pa . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Relevant Physics topic covering fundamental principles,
Given: A neutron ( 1 u ) at 6 × 10⁶m/s collides elastically with a deuterium ( 2 u ). What fraction of its kinetic energy is transferred? These values define the system as per NCERT data. Formula: Fraction transferred f_2 = 4 m_1 m_2/(m_1 + m_2)² = 4 × 1 × 2/(1 + 2)² = 8/9 approx 0.889 .. This is standard NCERT relation. Substitution & Calculation: Substituting values and simplifying step by step as per NCERT method. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.
Ref: NCERT Physics Textbook for Class XI and XII, Chapter: Relevant Physics topic covering fundamental principles,
Given: What is the EMF of a ll with Ni(s) | Ni²⁺(0.005 M) || Ag⁺(0.001 M) | Ag(s) at 298 K, given E_{Ni^{2+/Ni⁰ = -0.25 V and E_{Ag^{+/Ag⁰ = 0.80 V ? These values define the system as per NCERT data. Formula: E_{ll⁰ = 0.80 - (-0.25) = 1.05 V, n = 2. This is standard NCERT relation. Substitution & Calculation: E_{ll = E_{ll⁰ - 0.059/2 log frac[Ni^{2+][Ag^{+]² . Q = 0.005/(0.001)² = 5000, log Q = 3.699 . E_{ll = 1.05 - 0.059/2 × 3.699 = 1.05 - 0.109 = 0.941 V approx 0.94 V . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.
Ref: NCERT Chemistry Textbook for Class XI and XII, Chapter: Some Basic Concepts, Structure of Atom, Periodicity and relevant Chemistry topic, Topic: Mole concept and periodic trends.
