Skip to content

NEET MOCK TEST 16

NEET Mock Test 16 is another practice test in the NEET series, built to help you rehearse the exam under timed conditions. It covers questions from the main NEET subjects so you can measure progress across attempts and identify weak topics. Review the answers after submitting to understand where marks were lost.

180 questions

Why do echinoderms exhibit bilateral symmetry in their larval stage but radial symmetry as adults?

Larval Stage: Bilateral symmetry enables free-swimming larvae to balance and move efficiently in open water. Adult Stage: Adult echinoderms live on the seafloor (benthic zone). Pentaradial symmetry allows them to feed and detect surroundings equally from all directions.

Ref: NCERT Biology Textbook - Latest Edition for Academic Session 2026-27 (Zoology section, Rationalized Textbook for Class XI and XII), Chapter: Biology - Zoology portion (Latest NCERT Textbooks for Academic Session 2026-27 - Rationalized Edition for Class XI and XII), Topic: Structural organization, ph

Which amine can be synthesized from CH₃CH₂CH₂Br using Gabriel phthalimide synthesis?

Gabriel phthalimide synthesis converts primary alkyl halides like CH₃CH₂CH₂Br to primary amines, yielding CH₃CH₂CH₂NH₂ (propan-1-amine). This follows from latest NCERT 2026-27 principle explaining the concept clearly for NEET students in simple steps as per rationalized syllabus.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

Which complex produces 1 mole of AgCl per mole when treated with excess AgNO₃ ?

[CoCl₂(NH₃)4]Cl has one ionizable Cl^- outside the coordination sphere, yielding 1 mole of AgCl, while the two inside are non-ionizable. This follows from latest NCERT 2026-27 principle explaining the concept clearly for NEET students in simple steps as per rationalized syllabus.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

What is the oxidation number of oxygen in OF₂ ?

In OF₂, F is -1 (more electronegative), sum is zero: x + 2(-1) = 0, x - 2 = 0, x = +2 . This follows from latest NCERT 2026-27 principle explaining the concept clearly for NEET students in simple steps as per rationalized syllabus.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

The oxidation state of cobalt in CoCl₂ is:

In CoCl₂, Cl = -1 (2 chlorines = -2). For neutrality, Co = +2. This follows from latest NCERT 2026-27 principle explaining the concept clearly for NEET students in simple steps as per rationalized syllabus.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

What is the oxidation state of cobalt in [Co(en)2Cl₂]Cl ?

Given: What is the oxidation state of cobalt in [Co(en)2Cl₂]Cl ? Formula: The complex charge is +1 (balanced by 1 Cl⁻), so Co’s oxidation state is x - 2 = +1, x = +3 .. Substitution & Calculation: In [Co(en)2Cl₂]+, 2 en are neutral, 2 Cl^- contribute -2. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII), Chapter: Electrochemistry (Latest NCERT 2026-27), Topic: Faraday's laws, charge required to reduce Al³⁺, 3F = 3 × 96500 C

What is the oxidation state of chromium in the dichromate ion Cr₂O₇^{2- ?

Given: What is the oxidation state of chromium in the dichromate ion Cr₂O₇^{2- ? Formula: In Cr₂O₇^{2-, O = -2 (7 oxygens = -14). Substitution & Calculation: Let Cr = x. Then, 2x - 14 = -2, so 2x = 12, x = +6 . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

A reaction follows Rate = k[A][B]² with k = 0.1 L² mol^{-2 s^{-1, [A] = 0.2 M, and [B] = 0.4 M. What is the rate in mol

Given: A reaction follows Rate = k[A][B]² with k = 0.1 L² mol^{-2 s^{-1, [A] = 0.2 M, and [B] = 0.4 M. What is the rate in mol L^{-1 s^{-1 ? Formula: Rate = k[A][B]² = 0.1 × 0.2 × (0.4)² = 0.1 × 0.2 × 0.16 = 0.0032 .. Substitution: Substituting given values into formula as per NCERT 2026-27 method. Calculation: Simplifying step by step with proper SI units like m/s², J kg⁻¹ K⁻¹, 10⁻⁵, A m⁻¹ etc. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

Calculate the boiling point elevation of a solution containing 9 g of urea ( NH₂CONH₂ ) in 200 g of water. ( K_b = 0.52

Given: Calculate the boiling point elevation of a solution containing 9 g of urea ( NH₂CONH₂ ) in 200 g of water. ( K_b = 0.52 K kg/mol, Molar mass of urea = 60 g/mol ) Formula: Moles of urea = 9/60 = 0.15 mol. Substitution & Calculation: Molality = 0.15/0.2 = 0.75 mol/kg . Δ T_b = 0.52 × 0.75 = 0.39 K . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII), Chapter: Solutions (Latest NCERT 2026-27), Topic: Colligative properties, ΔT_b = K_b·m, urea NH₂CONH₂ example

For 2NO₂(g) N₂(g) + 2O₂(g), K_c = 0.25 at 600 K. If initial [NO₂] = 0.4 M, what is [O₂] at equilibrium?

Given: For 2NO₂(g) N₂(g) + 2O₂(g), K_c = 0.25 at 600 K. If initial [NO₂] = 0.4 M, what is [O₂] at equilibrium? Formula: Let [N₂] = x, [O₂] = 2x, [NO₂] = 0.4 - 2x. Substitution & Calculation: K_c = frac[N₂][O₂]²[NO₂]² = x (2x)²/(0.4 - 2x)² = 0.25 . 4x³/(0.4 - 2x)² = 0.25, solve: x approx 0.05, 2x = 0.1 M. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Chemistry Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII)Topic: Mole concept, atomic structure, chemical formulas like H₂O, CO₂, CH₃CH₂NH₂ and periodic trends.

A rod of length 0.25 m moves at 3 m/s in a 0.4 T field perpendicular to its length. What is the induced emf?

Given: A rod of length 0.25 m moves at 3 m/s in a 0.4 T field perpendicular to its length. What is the induced emf? Formula: ε = B l v = 0.4 × 0.25 × 3 = 0.3 V .. Substitution: Substituting given values into formula as per NCERT 2026-27 method. Calculation: Simplifying step by step with proper SI units like m/s², J kg⁻¹ K⁻¹, 10⁻⁵, A m⁻¹ etc. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Physics Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII, continuing as per NCERT advisory for 2026-27),Topic: Fundamental laws, definitions and applications as per latest NCERT. The section explains governing laws, formulas like μ₀ = 4π.

A square loop of side 0.18 m with 30 turns carries 2 A in a magnetic field of 0.4 T . The plane of the loop is at 60° to

Given: A square loop of side 0.18 m with 30 turns carries 2 A in a magnetic field of 0.4 T . The plane of the loop is at 60° to the field. What is the torque? Formula: Torque tau = N I A B sin θ, where A = 0.18 × 0.18 = 0.0324 m². Substitution & Calculation: tau = 30 × 2 × 0.0324 × 0.4 × sin 60° = 0.7776 × 0.866 = 0.6734 approx 0.67 N m . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Physics Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII, continuing as per NCERT advisory for 2026-27),Topic: Fundamental laws, definitions and applications as per latest NCERT. The section explains governing laws, formulas like μ₀ = 4π.