Practice question

Given: The de Broglie wavelength of a particle of mass 2.0 × 10⁻³⁰kg moving at 1.5 × 10⁶m/s is: Formula: p = m v = 2.0 × 10⁻³⁰ × 1.5 × 10⁶= 3.0 × 10⁻²⁴kg m/s. Substitution & Calculation: lambda = h/p = frac6.63 × 10⁻³⁴³.0 × 10⁻²⁴= 2.21 × 10⁻¹⁰m = 0.221 nm . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.