Practice question
Question
What is the phase difference corresponding to a path difference of 5lambda/4 in a double-slit experiment?
Explanation
Given:
What is the phase difference corresponding to a path difference of 5lambda/4 in a double-slit experiment?
Formula:
Phase difference phi = 2π/lambda Δ.
Substitution & Calculation:
For Δ = 5lambda/4, phi = 2π/lambda · 5lambda/4 = 5π/2 .
Final Result:
The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
Discussion
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