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#wave optics

3 public questions tagged with this topic.

What is the phase difference corresponding to a path difference of 5lambda/4 in a double-slit experiment?

Given: What is the phase difference corresponding to a path difference of 5lambda/4 in a double-slit experiment? Formula: Phase difference phi = 2π/lambda Δ. Substitution & Calculation: For Δ = 5lambda/4, phi = 2π/lambda · 5lambda/4 = 5π/2 . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.

Ref: NCERT Physics Textbook - Latest Edition for Academic Session 2026-27 (Rationalized Textbook for Class XI and XII, continuing as per NCERT advisory for 2026-27), Chapter: Wave Optics (Latest NCERT 2026-27), Topic: Interference, phase difference φ = (2π/λ)Δ, path difference 5λ/4 and double-slit experiment. The section explains governing laws, formulas like μ₀ = 4π × 10⁻⁷ T·m/A, SI units and illustrative examples. Page number.