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Practice question

Question

A square loop of side 25 cm rotates at 8 rad/s in a 0.15 T field. What is the maximum emf induced?

Options

Choose one · Correct answer highlighted

Explanation

Given: A square loop of side 25 cm rotates at 8 rad/s in a 0.15 T field. What is the maximum emf induced? These values define the system as per NCERT data. Formula: A = (0.25)² = 0.0625 m². This is the standard NCERT relation for this phenomenon. Substitution & Calculation: varepsilon_0 = N B A omega = 1 × 0.15 × 0.0625 × 8 = 0.075 V . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

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