Practice question

Given: A particle in SHM has an amplitude of 10 cm and a period of 0.5 s . What is its maximum velocity? (Take π = 3.14 ) These values define the system as per NCERT data. Formula: Maximum velocity: v_{max = A omega. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: omega = 2π/T = 2 × 3.14/0.5 = 12.56 rad/s . A = 0.1 m . v_{max = 0.1 × 12.56 = 1.256 m/s . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.