Practice question

Given: A photon of wavelength 300 nm is incident on a metal. What is its energy in eV? (Take h c = 1240 eV nm ) These values define the system as per NCERT data. Formula: Energy E = h c/lambda. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: E = 1240/300 approx 4.13 eV . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.