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Question

Vectors a\=2i^+6j^ and b\=5i^−3j^ are given. What is the magnitude of a×b?

Options

Choose one · Correct answer highlighted

Explanation

a×b = |i^j^k^2605−30| = k^(2×(−3)−6×5) = k^(−6−30) = −36k^. Magnitude = 36. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 36. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.