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a×b = |i^j^k^2605−30| = k^(2×(−3)−6×5) = k^(−6−30) = −36k^. Magnitude = 36. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 36. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
Projectile motion splits into horizontal uniform and vertical accelerated motion per NCERT Chapter 4. Range R=u²sin2θ/g and max height H=u²sin²θ/2g. Using given u, θ, g, calculation yields 90°. Hence option C satisfies projectile formulas.
Ref: NCERT Class 11 Physics > Chapter 4: Motion in a Plane > Topic: Projectile and Circular Motion Basics
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