Practice question
Question
Vectors a\=8i^−3j^ and b\=2i^+7j^ are given. What is the magnitude of a×b?
Explanation
a×b = |i^j^k^8−30270| = k^(8×7−(−3)×2) = k^(56+6) = 62k^. Magnitude = 62. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 62. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.