Skip to content

Question

A force F\=6i^−2j^N acts at r\=3i^+4j^m. What is the magnitude of the torque about the origin?

Options

Choose one · Correct answer highlighted

Explanation

τ = r×F = |i^j^k^3406−20| = k^(3×(−2)−4×6) = k^(−6−24) = −30k^Nm. Magnitude = 30Nm. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 30 Nm. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.