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#relative motion

2 public questions tagged with this topic.

A rocket is launched vertically at 60m/s from the ground. After 5s, a second rocket is launched at 45m/s. How long after

First: y1=60t−5t2, second: y2=45(t−5)−5(t−5)2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 5 s as the result, so option B is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Uniform Acceleration and Graphical Analysis

Two stones are released from a height of 98m, 1s apart. How long after the second stone is released do they meet? (Take

Stone 1: y1=12⋅9.8⋅(t+1)2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 12 as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Motion in a Straight Line - Advanced Problems