Practice question
Question
Two stones are released from a height of 98m, 1s apart. How long after the second stone is released do they meet? (Take g\=9.8m/s2)
Explanation
Stone 1: y1=12⋅9.8⋅(t+1)2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 12 as the result, so option A is correct.