#suvat equations

Motion in a Straight Line - Advanced Problems

Two stones are released from a height of 98m, 1s apart. How long after the second stone is released do they meet? (Take

Stone 1: y1=12⋅9.8⋅(t+1)2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 12 as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Motion in a Straight Line - Advanced Problems

View Details

Motion in a Straight Line - Advanced Problems

A stone falls freely from a height of 98m. How long does it take to reach the ground? (Take g\=9.8m/s2)

For free fall, use y=12gt2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 12 gt as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Motion in a Straight Line - Advanced Problems

View Details

Motion in a Straight Line - Advanced Problems

A stone is thrown upwards at 35m/s from a 45m cliff. How far below the cliff’s edge is it after 8s? (Take g\=10m/s2)

Displacement: y=35⋅8−12⋅10⋅(8)2=280−320=−40m. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 85 m as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Motion in a Straight Line - Advanced Problems

View Details

Motion in a Straight Line - Advanced Problems

A train moving at 126km/h decelerates at 2m/s2 for 10s, then at 5m/s2 until it stops. What is the total distance covered

Speed: 126km/h=35m/s. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 35 m/s as the result, so option A is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Motion in a Straight Line - Advanced Problems

View Details

Motion in a Straight Line - Advanced Problems

A truck moving at 15m/s decelerates uniformly and stops after 30m. How long does it take to stop?

Use v2=v02+2ax to find a: 0=(15)2+2a(30)⇒0=225+60a⇒a=−3.75m/s2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 4 s as the result, so option C is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Motion in a Straight Line - Advanced Problems

View Details

Motion in a Straight Line - Advanced Problems

A stone falls from a height of 98m on a planet and takes 3.5s to reach the ground. What is the gravitational acceleratio

h=12gt2, 98=12g(3.5)2⇒98=6.125g⇒g=16m/s2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 16 m/s² as the result, so option D is correct.

Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Motion in a Straight Line - Advanced Problems

View Details