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Practice question

MCQ

Question

A rocket is launched vertically at 60m/s from the ground. After 5s, a second rocket is launched at 45m/s. How long after the second launch do they meet? (Take g\=10m/s2)

Options

Choose one · Correct answer highlighted

Explanation

First: y1=60t−5t2, second: y2=45(t−5)−5(t−5)2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 5 s as the result, so option B is correct.

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