42 public questions tagged with this topic.
For adiabatic process, T₂ = T₁ (V₁/V₂)γ⁻¹ = 400 × (2/4)⁰.⁶⁷ ≈ 400 × 0.62996 = 252.0 K .
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Third Law of Thermodynamics and Applications
For reversible isothermal expansion, w = -nRT ln(V₂/V₁), where V₂ > V₁.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Heat Capacity and Calorimetry and Measurement of Enthalpy
w = -Pext Δ V = -1 × (5 - 2) × 101.3 = -1 × 3 × 101.3 = -303.9 J.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Enthalpy Changes - Reaction Formation Combustion and Hess's Law
T₂ = T₁ (V₁/V₂)γ⁻¹ = 600 × (10/25)⁰.⁵ = 600 × (0.4)⁰.⁵ = 600 × 0.632 = 379.2 K.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Enthalpy Changes - Reaction Formation Combustion and Hess's Law
Transitions: 5→2, 5→3→2, 5→4→2, 4→2, 3→2. Total = 5.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
n=4. E₄ = -13.6/16 = -0.85 eV.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
r₄(H)/r₃(Be³⁺) ≈ 7.11.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
Transitions: 7→4, 7→5→4, 7→6→4, 6→4, 5→4. Total = 5.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
n=3, l=1 corresponds to 3p orbital.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
Δv ≥ h/(4π m Δx) ≈ 5.8×10⁵ m s⁻¹.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Shapes of Orbitals - s p d f and Nodes and Radial Probability
Δp = m Δv. Δx ≥ h/(4π Δp) ≈ 5.8×10⁻¹¹ m.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Numbers - Principal Azimuthal Magnetic Spin
Δx ≥ h/(4π Δp) ≈ 5.79×10⁻¹¹ m.
Ref: NCERT Class 11 Chemistry > Chapter 2: Structure of Atom > Topic: Quantum Mechanical Model - de Broglie Heisenberg and Schrodinger
